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Ruin Probability Engine

Calculate the probability of ultimate bankruptcy for an insurance company using the Cramér-Lundberg model. Model premium inflow vs. random claim shocks with initial surplus and safety loading.

Model the continuous cash flow of premium intake versus random claim shocks to calculate the absolute probability of ultimate bankruptcy.

Actuarial Parameters

$
$

E.G. Claims per Year

$

Cramér-Lundberg Ruin

Infinite-Time Probability of Ruin

2.9728%

Survival Probability

97.0272%
1 - ψ(u)
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Quick Answer: How does the Ruin Probability Calculator work?

Enter initial surplus, safety loading factor, and mean claim size. The calculator applies the Cramér-Lundberg formula for exponential claims to compute the probability that the insurer's surplus will ever reach zero over infinite time.

Ruin Probability Formula

ψ(u) = (1/(1+θ)) × exp(-θu/((1+θ)μ)) | Ruin certain when θ ≤ 0

Where u = initial surplus, θ = safety loading, μ = mean claim size. Valid for exponentially distributed claims.

Industry Applications

Regulatory Capital (Solvency II)

European insurers must maintain capital sufficient for a 99.5% survival probability over one year (ruin probability < 0.5%). The Cramér-Lundberg model provides the theoretical basis for computing the minimum capital requirement (MCR) and solvency capital requirement (SCR).

Reinsurance Pricing

Reinsurers use ruin theory to price excess-of-loss treaties. The safety loading θ must be set high enough to ensure the reinsurer's own ruin probability stays below their risk appetite — typically ψ(u) < 0.01% for large commercial reinsurers like Swiss Re or Munich Re.

Impact of Safety Loading θ on Ruin Probability

Safety Loading θ ψ(0) (No Surplus) ψ(10μ) Interpretation
5%95.2%58.4%Dangerously thin margin
10%90.9%35.5%Below regulatory minimum
25%80.0%10.7%Moderate commercial level
50%66.7%2.44%Conservative insurer
100%50.0%0.10%Very heavily capitalized

Actuarial Best Practices (Pro Tips)

Do This

  • Stress-test with u = 0. The ruin probability at zero surplus ψ(0) = 1/(1+θ) is a critical benchmark. If this exceeds your risk tolerance, even large surplus cannot save you — the business model needs restructuring.

Avoid This

  • Don't assume exponential claims for heavy-tailed risks. Property catastrophe, cyber, and liability claims have heavy tails (Pareto, lognormal). The exponential formula dramatically underestimates ruin probability for these lines — use simulation or Pollaczek-Khinchine methods instead.

Frequently Asked Questions

What happens when safety loading θ = 0?

When θ = 0, premiums exactly equal expected claims — there is no profit margin. Ruin is mathematically certain (ψ = 100%) regardless of initial surplus. The surplus performs a random walk with zero drift and will inevitably hit zero. This is why the net profit condition θ > 0 is fundamental.

Why does the model assume infinite time?

The infinite-time horizon gives the worst-case scenario — the probability that ruin EVER occurs. Finite-time ruin probabilities are always lower (less time for bad luck to accumulate) but require numerical methods to compute. The infinite-time formula provides a conservative upper bound useful for capital adequacy.

What is the adjustment coefficient R?

R is the unique positive solution to the Lundberg equation: (1+θ)μR = M_X(R) - 1, where M_X is the moment generating function of claims. For exponential claims, R = θ/((1+θ)μ). Larger R means faster exponential decay of ruin probability with surplus — a safer insurer.

How does this relate to Solvency II regulations?

Solvency II requires European insurers to hold enough capital for a 99.5% one-year survival probability. While regulators use more complex models (internal models, standard formula), the Cramér-Lundberg framework provides the theoretical foundation. The adjustment coefficient R directly links to the solvency capital requirement.

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