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Quadratic Formula Engine

Solve any quadratic equation using the quadratic formula. Handles real, repeated, and complex roots with full discriminant analysis, vertex coordinates, and axis of symmetry.

ax² + bx + c = 0

1x² + -3x + 2 = 0
Two Real Roots
Root 1 (x₁)2
Root 2 (x₂)1
Discriminant (Δ)1
Vertex(1.5, -0.25)
Axis of Symmetryx = 1.5
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The Quadratic Formula

For any quadratic equation ax² + bx + c = 0, the solutions are given by: x = (−b ± √(b² − 4ac)) / 2a.

The Discriminant (Δ)

  • Δ = b² − 4ac
  • Δ > 0: Two distinct real roots
  • Δ = 0: One repeated real root (the parabola touches the x-axis)
  • Δ < 0: Two complex/imaginary roots (no real x-intercepts)

Vertex & Axis of Symmetry

  • Axis of Symmetry: x = −b / 2a
  • Vertex: (−b/2a, f(−b/2a)) — the minimum or maximum point

Factoring Check 💡

If both roots are integers, the equation factors nicely: (x − r₁)(x − r₂) = 0. Try a=1, b=−3, c=2 → roots are 2 and 1 → factors as (x−2)(x−1) = 0.

What is The Quadratic Formula: Universal Root Finder for Degree-2 Polynomials?

The quadratic formula solves any equation of the form ax² + bx + c = 0 by expressing roots directly in terms of coefficients. Derived by completing the square on the general form, it handles all cases: two distinct real roots, one repeated root, or two complex conjugate roots. The discriminant Δ = b² − 4ac determines which case applies. First documented by Brahmagupta in 628 AD, it remains the most-used algebraic formula across STEM education and engineering.

Mathematical Foundation

The Quadratic Formula
x=−b±b2−4ac2a,Δ=b2−4acx = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, \quad \Delta = b^2 - 4ac
aa= Coefficient of x² (must be non-zero). Controls parabola width and direction.
bb= Coefficient of x. Shifts the vertex horizontally.
cc= Constant term (y-intercept when x = 0).
Δ\Delta= Discriminant: Δ > 0 → 2 real roots. Δ = 0 → 1 repeated root. Δ < 0 → 2 complex roots.

Laws & Principles

  • Discriminant Classification: Δ > 0 gives two distinct real roots. Δ = 0 gives one repeated root (the parabola touches the x-axis at exactly one point). Δ < 0 produces complex conjugate roots a ± bi — the parabola never crosses the x-axis. The sign of Δ alone determines the nature of solutions.
  • Vieta's Formulas: For ax² + bx + c = 0, the sum of roots = −b/a and the product of roots = c/a. These elegant relationships let you verify solutions without plugging back in: if root₁ + root₂ ≠ −b/a, you made an error.
  • Vertex Form Conversion: Every parabola y = ax² + bx + c can be rewritten as y = a(x − h)² + k, where h = −b/(2a) is the x-coordinate and k = c − b²/(4a) is the y-coordinate of the vertex. The vertex is the minimum (a > 0) or maximum (a < 0) point.

Step-by-Step Example Walkthrough

" Solve 2x² − 7x + 3 = 0. Here a = 2, b = −7, c = 3. "

  1. 1. Discriminant: Δ = (−7)² − 4(2)(3) = 49 − 24 = 25.
  2. 2. Δ > 0 → two distinct real roots.
  3. 3. x = (7 ± √25) / (2×2) = (7 ± 5) / 4.
  4. 4. Root 1: (7 + 5)/4 = 3. Root 2: (7 − 5)/4 = 0.5.
Final Result: x = 3 and x = 0.5. Verify: sum = 3.5 = 7/2 = −b/a ✓. Product = 1.5 = 3/2 = c/a ✓. Vertex at x = 7/4 = 1.75, y = 2(1.75)² − 7(1.75) + 3 = −3.125.

Quick Answer: How does the Quadratic Formula Solver work?

Enter coefficients a, b, and c for ax² + bx + c = 0. The solver computes the discriminant, both roots (real or complex), vertex coordinates, and axis of symmetry.

The Formula

x = (−b ± √(b²−4ac)) / 2a | Discriminant Δ = b²−4ac

Δ > 0 → 2 real roots | Δ = 0 → 1 repeated root | Δ < 0 → 2 complex roots (a±bi)

Applications

Physics Trajectory Problems

When a ball is thrown upward at velocity v₀, its height is h(t) = −½gt² + v₀t + h₀. Setting h(t) = 0 creates a quadratic equation whose positive root gives the time to hit the ground. The vertex gives the maximum height and the time at which it occurs — both critical for engineering.

Break-Even Analysis

Revenue curves R(x) = px and cost curves C(x) = ax² + bx + c (diminishing returns) intersect at break-even points found by solving ax² + (b−p)x + c = 0. The discriminant tells you whether break-even is possible (Δ ≥ 0) or if costs always exceed revenue (Δ < 0).

Discriminant Quick Reference

Discriminant (Δ) Root Type Graph Behavior Example
Δ > 0Two distinct real rootsParabola crosses x-axis twicex² − 5x + 6 = 0 → x = 2, 3
Δ = 0One repeated rootParabola touches x-axis oncex² − 4x + 4 = 0 → x = 2
Δ < 0Two complex conjugate rootsParabola never crosses x-axisx² + 1 = 0 → x = ±i

Algebra Best Practices (Pro Tips)

Do This

  • ✓Use Vieta's formulas to verify. Check that root₁ + root₂ = −b/a and root₁ × root₂ = c/a. This catches sign errors and arithmetic mistakes instantly without substituting back into the original equation.

Avoid This

  • ✗Don't forget to rearrange to standard form first. The formula requires ax² + bx + c = 0 (one side equals zero). An equation like 3x² = 5x − 2 must be rewritten as 3x² − 5x + 2 = 0 before identifying a=3, b=−5, c=2. Skipping this step produces wrong signs.

Frequently Asked Questions

What does the discriminant tell you?

The discriminant Δ = b² − 4ac tells you how many and what type of solutions exist. Positive → two real roots (parabola crosses x-axis twice). Zero → one repeated root (parabola touches x-axis). Negative → two complex conjugate roots (parabola never reaches x-axis).

What are complex roots?

When Δ < 0, the square root of a negative number produces imaginary terms (i = √−1). Roots appear as conjugate pairs: a + bi and a − bi. Complex roots are crucial in electrical engineering (AC circuit analysis), control theory, and signal processing, even though they have no position on the real number line.

How do I find the vertex of a parabola?

The vertex is at x = −b/(2a), y = c − b²/(4a). This point is the minimum (when a > 0, parabola opens upward) or maximum (when a < 0, parabola opens downward) of the quadratic function. The axis of symmetry is the vertical line x = −b/(2a).

When should I factor instead of using the formula?

Factor when the discriminant is a perfect square and the roots are simple integers or fractions (e.g., x² − 5x + 6 = (x−2)(x−3)). The quadratic formula always works but is overkill for simple cases. If Δ is not a perfect square, the formula is faster and more reliable than trial-and-error factoring.

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