What is Geotechnical Soil Mechanics & Shallow Foundation Design?
Mathematical Foundation
Laws & Principles
- Cohesion Term (c·Nc): Represents the shear strength of strictly cohesive soil particles sticking together. In heavily saturated clays where the friction angle (φ) drops near 0°, this is the only term that matters—the soil fails in rapid undrained shear. In clean river sands, cohesion c = 0 and this entire term mathematically vanishes.
- Surcharge Term (γ·Df·Nq): The physical weight of the dirt sitting directly above the footing elevation acts like a giant, heavy blanket creating confining pressure that ruthlessly resists the passive wedge pushing upward. Deeper footings dramatically improve capacity — burying a footing twice as deep roughly doubles this defensive term.
- Density Term (0.5·γ·B·Nγ): The sheer internal friction contribution from the actual mass of the soil wedge trapped beneath the footing. Wider footings mobilize a vastly wider, deeper frictional failure arc. This term grows linearly with footing width (B), which is why massive monolithic mat foundations can achieve extraordinary capacities in deep granular soils.
- The Global Factor of Safety: FS = 3.0 is the unforgiving industry standard for bearing capacity. It is NOT applied to settlement predictions — a totally separate deformation analysis (e.g., Terzaghi primary consolidation or Boussinesq elastic settlement) is legally required alongside the initial bearing capacity check.
- Groundwater Table Destruction: If the unseen groundwater table rises up to the footing elevation, the soil becomes instantly buoyant. You must replace the dry unit weight with the submerged effective unit weight (γ' ≈ γ_sat - 62.4). This single water event instantly reduces the foundation capacity by an overwhelming 40%.
Step-by-Step Example Walkthrough
" A structural engineer is designing a load-bearing wall strip footing in medium-density silt-clay. Laboratory borings show soil cohesion c = 200 psf, unit weight γ = 110 pcf. The architect sets the footing depth Df = 3 ft and footing width B = 4 ft. The Triaxial test friction angle φ = 20°, which references chart factors: Nc = 17.7, Nq = 7.4, Nγ = 5.0. "
- 1. Calculate Cohesion term: 200 psf × 17.7 (Nc) = 3,540 psf of resistance.
- 2. Calculate Surcharge term: 110 pcf × 3 ft deep × 7.4 (Nq) = 2,442 psf of resistance.
- 3. Calculate Density term: 0.5 × 110 pcf × 4 ft wide × 5.0 (Nγ) = 1,100 psf of resistance.
- 4. Calculate Ultimate Failure (q_u): 3,540 + 2,442 + 1,100 = 7,082 psf ultimate capacity.
- 5. Apply Life Safety Limit: q_safe = 7,082 / 3.0 (Factor of Safety) = 2,361 psf usable capacity.