What is The Constant Volume Metal Removal Method for Threading?
Mathematical Foundation
Laws & Principles
- Why Linear Depths Fail: If you take 5 equal-depth passes of 0.006' to hit a 0.030' thread depth, Pass 1 removes a tiny triangle of metal. Pass 5 removes a massive trapezoid that contains 9 times more metal than Pass 1. The machine will chatter violently and the tool will break.
- Spring Passes: The theoretical formula gets the tool to the exact theoretical pitch diameter. In reality, tool deflection pushes the insert away from the cut. Always program 1 or 2 extra 'spring passes' (cutting at the final depth without feeding deeper) to clean up deflection and hit pitch tolerances.
- Straight vs. Modified Flank Infeed: In straight infeed, the tool plunges straight in radially (Z-axis is static, X feeds in). This creates a V-shaped chip that pinches and jams in the thread root. CNC programmers prefer 'Modified Flank Infeed' (G76 cycle), which feeds the tool in at a 29-29.5 degree angle. The tool cuts entirely on its leading edge, rolling the chip out of the groove smoothly.
- Threading Speed Limit: Threading speed (RPM) is limited by the CNC control's servo lag. If RPM is too high, the Z-axis servo cannot accelerate to the required feed rate in time to sync with the spindle rotation, leading to a destroyed thread pitch. Threading is typically done slower than normal turning.
Step-by-Step Example Walkthrough
" Turning a 1/2-13 UNC external thread. Pitch = 1/13 = 0.0769'. Doing it in 5 passes. "
- 1. Calculate Total Depth: Dt = 0.6134 × 0.0769' = 0.0472' total radial depth.
- 2. Pass 1: 0.0472 × √(1/5) = 0.0211' cumulative depth (Depth of cut: 0.0211')
- 3. Pass 2: 0.0472 × √(2/5) = 0.0298' cumulative depth (Depth of cut: 0.0087')
- 4. Pass 3: 0.0472 × √(3/5) = 0.0365' cumulative depth (Depth of cut: 0.0067')
- 5. Pass 4: 0.0472 × √(4/5) = 0.0422' cumulative depth (Depth of cut: 0.0057')
- 6. Pass 5: 0.0472 × √(5/5) = 0.0472' cumulative depth (Depth of cut: 0.0050')