What is The Geometry of Circular Interpolation and Feed Rates?
Mathematical Foundation
Laws & Principles
- The Internal Ratio Rule: Look at the internal equation. The ratio is (Hole - Tool) / Hole. If you have a 1-inch hole and a 0.5-inch tool, the ratio is 50%. This means the cutting edge is traveling exactly twice as fast as the centerline. Therefore, you must cut your programmed feed rate in half to achieve the correct chip load.
- The Crash Radius Rule: For internal threading, the tool diameter must ALWAYS be smaller than the hole diameter. If they are equal, the ratio becomes zero, meaning the tool is fully enveloped and rubbing against the entire inner wall of the hole simultaneously.
- External Requires Speeding Up: When milling an external boss, the tool centerline travels on a LARGER circle than the cutting edge. Therefore, the cut edge is lagging behind. You must actually INCREASE your programmed feed rate to maintain the correct chip load during external circular interpolation.
- Modern CAM Compensation: Most modern CAM systems (Mastercam, Fusion 360) will automatically calculate this compensation if the 'Centerline Feed' option is checked. However, if you are hand-typing G02/G03 loops at the control, applying this formula is absolutely critical.
Step-by-Step Example Walkthrough
" A machinist is hand-programming an internal thread mill cycle. Hole Diameter is 2.0 inches. Tool Diameter is 1.5 inches. The tooling catalog requests a feed rate of 30 IPM to hit the proper chip thickness. "
- 1. Identify the operation: Internal.
- 2. Find the Ratio: (Hole Dia - Tool Dia) / Hole Dia.
- 3. Substitute values: (2.0 - 1.5) / 2.0 = 0.5 / 2.0 = 0.25 (or 25%).
- 4. Calculate final Feed: F_center = 30 IPM × 0.25 = 7.5 IPM.