What is Hydro-Mechanical Grease Traps?
Mathematical Foundation
Laws & Principles
- Volume to Gallons Rule: 231 cubic inches equals exactly 1 liquid gallon. This is a universally essential plumbing math constant used to convert physical box dimensions into fluid capacity.
- The 75% Displacement Rule: When sizing traps based on sink bowl dimensions, you multiply the raw volume by 75% to achieve 'Operating Capacity'. Plumbers assume normal washing scenarios leave headroom, and submerged dishes displace water.
- Drain Time Surges: Standard code assumes an entire sink will be drained in 1 to 2 minutes. The faster the drain time configured, the larger the trap you need, because the trap must process the GPM surge without washing the grease cap down the drain.
- The 2-to-1 Pound Rule: According to the Plumbing and Drainage Institute (PDI), the grease retaining capacity in physical pounds shall be at least twice the flow rating in GPM. (e.g., A 50 GPM rated trap must securely hold 100 lbs of grease before its efficiency drops below 90%).
Step-by-Step Example Walkthrough
" A plumbing engineer is sizing a trap for a heavy-duty 3-compartment pot sink in a cafeteria. Each bowl measures 24-inch long, 24-inch wide, and 15-inch deep. Draining time is modeled for 2 minutes to save under-counter space. "
- 1. Total Volume in Cubic Inches: 24 × 24 × 15 × 3 compartments = 25,920 in³.
- 2. Convert to US Gallons: 25,920 ÷ 231 = 112.2 Gallons total capacity.
- 3. Apply Operating Displacement: 112.2 × 0.75 = 84.15 Gallons of actual draining fluid.
- 4. Calculate Peak Flow Rate: 84.15 Gallons ÷ 2 minutes = 42.07 GPM flow rate.
- 5. Apply PDI Multiplier: 42.07 GPM means 84.14 lbs of required minimum grease capacity.