What is Arcing Current Physics & IEEE 1584 Equations (<1kV)?
Mathematical Foundation
Laws & Principles
- IEEE 1584 Validity Envelope: Low-voltage model applies to three-phase AC systems between 208V and 1,000V with bolted fault currents from 0.7 kA to 106 kA.
- Arc Resistance Reduces Fault Current: Plasma impedance causes arcing current (I_a) to range between 40% and 85% of bolted current (I_bf). Protective trip times must be evaluated at I_a, not I_bf.
- NFPA 70E 85% Rule: Incident energy must be evaluated at 100% of I_a and 85% of I_a to capture longer clearing times caused by lower currents on inverse-time overcurrent protective curves.
- Conductor Gap Standards: IEEE 1584 standard baseline gaps are 32 mm for low-voltage switchgear, 25 mm for motor control centers (MCC) and panelboards, and 13 mm for shallow cable enclosures.
Step-by-Step Example Walkthrough
" Calculate the expected arcing current for a 480V (0.48 kV) motor control center with 25 kA bolted fault current, enclosed box geometry (K = -0.097), and a 25 mm bus gap. "
- 1. Calculate bolted current logarithm: log10(25) = 1.39794
- 2. Evaluate linear terms: -0.097 + (0.662 * 1.39794) + (0.0966 * 0.48) + (0.000526 * 25) = -0.097 + 0.92544 + 0.04637 + 0.01315 = 0.88796
- 3. Evaluate cross-product terms: (0.5588 * 0.48 * 1.39794) - (0.00304 * 25 * 1.39794) = 0.37494 - 0.10624 = 0.26870
- 4. Sum terms: log10(I_a) = 0.88796 + 0.26870 = 1.15666
- 5. Solve for arcing current: I_a = 10^1.15666 = 14.34 kA